Category: Basic Chemistry K-Scheme Lab Manual Answer

  • Practical No. 05: Determination of Electrode Potential of Iron

     Practical No. 05: Determination of Electrode Potential of Iron

    XIII. Interpretation of Results
    Electrochemical cell with zinc and iron electrodes produced measurable EMF. Iron’s reduction potential was calculated as approximately -0.44 volts, matching the standard value. Zinc is placed above iron in electrochemical series, indicating greater electropositivity.
    XIV. Conclusions and Recommendations
    • Conclusion: Zinc is more electropositive than iron (-0.76 V vs -0.44 V). Therefore zinc acts as sacrificial anode protecting iron from corrosion.
    • Recommendation: Use clean electrodes and fresh electrolyte solutions for accurate measurements.

    XV. Practical Related Questions & Answers
    Q1. Define De-electronation & Electronation.
    • Answer: De-electronation is the process of removal of electrons from an atom or ion, i.e., oxidation (loss of electrons). Electronation is the process of addition of electrons to an atom or ion, i.e., reduction (gain of electrons). At anode, de-electronation occurs, and at cathode, electronation occurs in an electrochemical cell.
    Q2. Write the factors influence the electrode potential of iron.
    • Answer: Factors influencing electrode potential of iron include:
      • (i) Nature of the metal and its ions.
      • (ii) Concentration of metal ions in solution.
      • (iii) Temperature of the solution.
      • (iv) Pressure (for gaseous electrodes).
      • (v) Nature of the electrolyte.
      • (vi) Surface condition of the electrode.

    Q3. Write the applications of the electrode potential of iron in industries or technologies.
    • Answer: Applications include:
      • (i) Designing corrosion protection systems like sacrificial anodes and cathodic protection.
      • (ii) Electroplating and galvanization of iron surfaces.
      • (iii) Manufacturing of batteries and electrochemical cells.
      • (iv) Determining the feasibility of redox reactions.
      • (v) Metallurgy and metal extraction processes.
      • (vi) Sensor and analytical applications.


  • Practical No. 04: Determination of Electrode Potential of Copper

     Practical No. 04: Determination of Electrode Potential of Copper

    XIII. Interpretation of Results
    Electrochemical cell with zinc and copper electrodes produced measurable EMF. Copper’s reduction potential was calculated using cell potential and known oxidation potential of zinc, matching the standard value of +0.34 volts. Zinc is placed above copper in electrochemical series.
    XIV. Conclusions and Recommendations
    • Conclusion: Zinc is more electropositive than copper (lower reduction potential -0.76 V vs +0.34 V). Hence zinc undergoes corrosion in preference to copper when in contact.
    • Recommendation: Clean electrode surfaces, use fresh solutions, and ensure proper connections for accurate readings.

    XV. Practical Related Questions & Answers
    Q1. Describe the chemical reactions at the cathode and anode in the experiment.
    • Answer:
      • At Anode (Zinc electrode – oxidation): Zn → Zn²⁺ + 2e⁻ (Zinc loses electrons and dissolves as Zn²⁺ ions).
      • At Cathode (Copper electrode – reduction): Cu²⁺ + 2e⁻ → Cu (Copper ions gain electrons and deposit as copper metal on the electrode).
      • Net Reaction: Zn + Cu²⁺ → Zn²⁺ + Cu.

    Q2. Explain the relation between the reduction electrode potential of a metal electrode and its tendency towards corrosion.
    • Answer: Lower reduction potential indicates a higher tendency to undergo oxidation (corrosion). Metals with more negative reduction potentials (like Zn, Fe) have a higher tendency to lose electrons and corrode. Metals with positive reduction potentials (like Cu, Ag) have a lower tendency to corrode. Thus, more electropositive metals corrode preferentially.
    Q3. Identify the cathode and anode in the given electrochemical cell.
    • Answer: Zinc electrode acts as the Anode (negative terminal) where oxidation occurs. Copper electrode acts as the Cathode (positive terminal) where reduction occurs. Electrons flow from zinc (anode) through the external circuit to copper (cathode), and conventional current flows from copper to zinc.

  • Practical No. 03: Identification of States of Matter

     Practical No. 03: Identification of States of Matter

    XIII. Interpretation of Results
    Simulation experiment demonstrated the three states of matter – solid, liquid, and gas. Particle arrangement and movement clearly illustrated characteristics of each state. Melting and boiling points determined from the plotted graph matched theoretical values.
    XIV. Conclusions and Recommendations
    • Conclusion: Matter exists in solid, liquid, and gas states depending on temperature and pressure.
    • Recommendation: Use simulation carefully, record observations systematically, and plot accurate graphs for precise determination of phase transition temperatures.

    XV. Practical Related Questions & Answers
    Q1. Write the characteristics of particles of matter.
    • Answer: Particles of matter have the following characteristics:
      • (i) They are continuously moving.
      • (ii) They have spaces between them.
      • (iii) They attract each other (intermolecular forces).
      • (iv) They are very small in size.
      • (v) The kinetic energy of particles increases with an increase in temperature.
      • (vi) The movement of particles decreases with a decrease in temperature.

    Q2. Write the factors that determine the physical state exhibited by a substance.
    • Answer: The physical state of a substance is determined by:
      • (i) Temperature: Increasing temperature changes solid to liquid and liquid to gas.
      • (ii) Pressure: Increasing pressure can change gas to liquid and liquid to solid.
      • (iii) Intermolecular forces: Stronger forces favour the solid state, while weaker forces favour the gaseous state.
      • (iv) Kinetic energy of particles: Higher kinetic energy favours the gaseous state.

    Q3. Write the physical state of water at 0°C, 100°C.
    • Answer:
      • At 0°C: Water exists in two states — solid (ice) and liquid (water) at the melting point (both coexist).
      • At 100°C: Water exists in two states — liquid (water) and gas (steam/water vapour) at the boiling point (both coexist).
      • Note: Above 0°C and below 100°C, water is purely in a liquid state.


  • Practical No. 02: Identification of Anions

     Practical No. 02: Identification of Anions

    XIII. Interpretation of Results
    Qualitative anion analysis successfully identified acidic radicals using group reagents. Gas evolution, coloured precipitates, and specific colour changes confirmed the presence of respective anions in the sample solutions.
    XIV. Conclusions and Recommendations
    • Conclusion: Systematic anion analysis with group reagents effectively identifies acidic radicals.
    • Recommendation: Use freshly prepared reagents, avoid contamination, and perform tests in proper sequence for accurate results.

    XV. Practical Related Questions & Answers
    Q1. Identify the acidic radical in solution ‘A’ by observing the release of CO₂ gas upon reacting with diluted nitric acid (HNO₃).
    • Answer: The acidic radical is CO₃²⁻ (Carbonate). When carbonate reacts with dilute HNO₃, it liberates CO₂ gas which turns lime water milky due to formation of CaCO₃. The effervescence observed confirms the presence of carbonate ion.
    Q2. Write the procedure for separating halides in a sample solution through a separation test.
    • Answer: To separate halides, add dilute HNO₃ followed by AgNO₃ solution. White precipitate indicates Cl⁻, pale yellow precipitate indicates Br⁻, and yellow precipitate indicates I⁻.
    • Confirmation: For further confirmation, add chloroform and chlorine water — chlorine water liberates halogens which dissolve in chloroform giving characteristic colours: Cl⁻ gives colourless layer, Br⁻ gives yellowish brown layer, and I⁻ gives violet layer.
    Q3. Identify the anion in solution ‘X’ when mixed with barium nitrate which gives white ppt.
    • Answer: The anion is SO₄²⁻ (Sulphate). Barium nitrate gives a white precipitate of BaSO₄ which is insoluble in dilute HNO₃. This confirms the presence of sulphate ion. The confirmatory test can also be performed using BaCl₂ solution which gives the same white precipitate.

  • Practical No. 01: Identification of Cations

    Practical No. 01: Identification of Cations
    XIII. Interpretation of Results
    Qualitative analysis successfully identified cations using group separation and confirmatory tests. Characteristic precipitates and colour reactions confirmed the presence of respective cations in the sample solutions.
    XIV. Conclusions and Recommendations
    • Conclusion: Systematic group-wise separation effectively identifies cations in unknown solutions.
    • Recommendation: Clean glassware, dropwise reagent addition, and careful confirmatory tests are recommended to avoid false results.

    XV. Practical Related Questions & Answers
    Q1. Identify the basic radical present in the given solution ‘A’ by observing the formation of a black precipitate with diluted hydrochloric acid (HCl) and the evolution of hydrogen sulfide (H₂S) gas.
    • Answer: The basic radical present is Cu²⁺ (Copper). A black precipitate of CuS is formed in group II when H₂S gas is passed through the solution containing Cu²⁺ ions in an acidic medium. Copper belongs to group II of qualitative analysis.
    Q2. Explain the process for identifying either the Ba²⁺ or Ca²⁺ radical in the unknown solution.
    • Answer: To distinguish between Ba²⁺ and Ca²⁺, add K₂CrO₄ solution to the original solution. Ba²⁺ gives a yellow precipitate of BaCrO₄, while Ca²⁺ gives no precipitate.
    • Alternative: Alternatively, perform a flame test — Ba²⁺ gives an apple green flame, and Ca²⁺ gives a brick red flame. Ammonium oxalate gives a white precipitate with Ca²⁺ which is insoluble in acetic acid.
    Q3. Identify the cation in solution ‘X’ by recognizing its pale green colouration, and when combined with sodium hydroxide, observe the formation of a dirty green-coloured precipitate.
    • Answer: The cation is Fe²⁺ (Ferrous ion). The pale green colour indicates Fe²⁺ ions. With NaOH, Fe²⁺ forms a dirty green precipitate of Fe(OH)₂. This can be confirmed by K₃[Fe(CN)₆] which gives a deep blue precipitate (Turnbull’s blue) with Fe²⁺.