Practical No. 05: Determination of equivalent resistance in series connection of resistors.

 Practical No. 05: Determination of equivalent resistance in series connection of resistors.

XIII. Interpretation of Results
  • The experimental value of the equivalent resistance in series (Rs) was found to be approximately equal to the sum of the individual resistances (R1 + R2).
XIV. Conclusions and Recommendations
  • It is concluded that for a series combination, the current remains the same through all resistors, but the voltage is shared.
  • It is recommended to use resistors whose values are sufficiently different to clearly observe the voltage division.

XV. Practical Related Questions & Answers
Q1. Write the function of rheostat in the circuit used.
  • Answer: The rheostat is used to vary the total current in the circuit. This allows us to obtain multiple sets of voltage and current readings for each resistor configuration, which improves the accuracy of the calculated resistance values.
Q2. Calculate the potential difference required to pass a current of 5A through a metallic rod of resistance 10Ω.
  • Answer:
    • Formula: Voltage (V) = Current (I) × Resistance (R)
    • Given Data:
      • Current (I) = 5 A
      • Resistance (R) = 10 Ω

    • Calculation:
      • V = 5 A × 10 Ω
      • V = 50 V

Q3. Three resistors of resistances 25Ω, 50Ω, and 75Ω respectively are connected in series in a circuit. What is the effective resistance of the combination of the three resistors?
  • Answer:
    • Formula for series: R_effective = R1 + R2 + R3
    • Given Data: R1 = 25 Ω, R2 = 50 Ω, R3 = 75 Ω
    • Calculation:
      • R_effective = 25 + 50 + 75
      • R_effective = 150 Ω

Q4. If the voltage across a fixed value of resistance is increased five times, what will be the variation in current?
  • Answer:
    • Explanation: From Ohm’s law, Current (I) = Voltage (V) / Resistance (R). If resistance (R) is constant and voltage is increased to 5V, the new current will also increase five times.

Q5. Three resistances of 15, 10, and 20 ohms are connected in series. Find the equivalent resistance for the system.
  • Answer:
    • Formula: R_equivalent = R1 + R2 + R3
    • Given Data: R1 = 15 Ω, R2 = 10 Ω, R3 = 20 Ω
    • Calculation:
      • R_equivalent = 15 + 10 + 20
      • R_equivalent = 45 Ω


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